Elimination is easier for most simultaneous equations. For complex equations involving non linear equations you may need to use/ verify with the substitution method.
4x + y = 13...(1) 2x + 3y =9...(2) |*Using elimination*| 2(4x + y = 13) 4(2x + 3y = 9) 8x + 2y = 26 -(8x + 12y = 36) -10y = -10 y = 1 |*Substitute y in (1)*| 4x +1 = 13 4x = 12 x = 12/4 = 3 |*Solutions *| x = 3, y =1
3x - y= 18....(1) 2x + y = 7...(2) |*Method of elimination*| 2(3x- y = 18) 3(2x + y = 7) 6x - 2y = 36 -(6x + 3y = 21) -5y = 36- 21 = 15 y = 15/-5 = -3 |*Substitute y in (1)*| 3x -(-3)= 18 3x +3 = 18 3x = 15 x = 15/3 = 5
8x + 2y = 13....(1) 3x + y = 4....(2) |*Using elimination*| 3(8x + 2y = 13) 8(3x + y = 4) 24x + 6y = 39 -(24x + 8y = 32) -2y = 7 y = -7/2 Put y in (1) 8x + 2(-7/2) = 13 8x -7 = 13 8x = 20 x = 20/8 = 5/2 |*Solutions*| x = 5/2, y = -7/2Verifying with Substitution
|*Pick an easy equation to make one term a subject. In (2) make y the subject*| y = 4 -3x Substitute y in (1) 8x + 2(4 - 3x)= 13 8x + 8 - 6x = 13 2x = 13 - 8 2x = 5 x = 5/2 |*Substitute x in (1) or (2)*| 8(5/2) +2y = 13 20 + 2y = 13 2y = -7 y = -7/2
6x +2y = 19....(1) 2x + 8y = 43....(2) 2(6x + 2y = 19) 6(2x + 8y = 43) 12x + 4y = 38 -(12x + 48y = 258) -44y = -220 y = -220/-44 = 5 |*Substitute 5 in (2) or (1)*| 2x + 8(5)= 43 2x = 43 - 40 x = 3/2
2x + 13y = 36.......(1) 13x + 2y = 69.......(2) 13(2x + 13y = 36) 2(13x + 2y = 69) 26x + 169y = 468 -(26x + 4y = 138) 165y =330 y = 330/ 165 = 2 |*Sub y = 2 in (1)*| 2x + 13(2) = 36 2x + 26 = 36 2x = 10 x = 10/2 = 5 Solutions x = 5, y= 2
7x - y = 15.....(1) 3x - 2y= 19......(2) 3(7x - y = 15) 7(3x -2y = 19) 21x - 3y = 45 -(21x - 14y = 133) 11y = -88 y = -88/11 = -8 |*Substitute y = -8 in (1)*| 7x - (-8) = 15 7x + 8 = 15 7x = 7 x =7/7 = 1 x =1, y = -8
2x - 5y = 22......(1) 2y - 3x = -11......(2) |*Using elimination*| |*Rearrange*| 2x - 5y = 22 -3x + 2y = -11 -3(2x - 5y = 22) 2(-3x + 2y = -11) -6x + 15y = -66 -(-6x + 4y = -22) 11y = -66 - (-22)= -44 y = -44/11 = -4 |*Substitute y = -4 in (1) or (2)*| 2x - 5(-4) = 22 2x + 20 = 22 2x = 20 - 22 x = 2/2 = 1
y = x@2 -1.....(1) y = 5 - x.....(2) |*Using substitution*| |*Make x subject*| x = 5 - y Substitute x in (1) y = (5 - y)_2 - 1 y = (5 - y)(5 - y) -1 |*Group like terms*| 25-5y - 5y -y -y@2- 1 = 0 -y@2 -11y + 24 = 0 -y@2 -8y -3y + 24 = 0 -y(y + 8)- 3(y + 8) = 0 (y + 8)(-y - 3 ) = 0 y = -8 or -3 |*Substitute -8 in (2)*| -8 = 5 - x x = 5 + 8 = 13 |*Substitute - 3 in (2)*| -3 = 5 -x x = 3 + 5 = 8 |*Solutions*| y = -8, x =13 and y= -3, x= 8 or (13, -8) and (8, -3)